x^2+6x=144

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Solution for x^2+6x=144 equation:



x^2+6x=144
We move all terms to the left:
x^2+6x-(144)=0
a = 1; b = 6; c = -144;
Δ = b2-4ac
Δ = 62-4·1·(-144)
Δ = 612
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{612}=\sqrt{36*17}=\sqrt{36}*\sqrt{17}=6\sqrt{17}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6\sqrt{17}}{2*1}=\frac{-6-6\sqrt{17}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6\sqrt{17}}{2*1}=\frac{-6+6\sqrt{17}}{2} $

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